Solution of equation by separation of variables

Now we need a functional form for ψ to solve the PDE.  Look at vrpsi above and realize that we need it to have a cos dependence.  Thus C[r] Sin[[Graphics:../Images/inviscid_sphere_gr_67.gif]] looks like a good choice.  

[Graphics:../Images/inviscid_sphere_gr_68.gif]
[Graphics:../Images/inviscid_sphere_gr_69.gif]
[Graphics:../Images/inviscid_sphere_gr_70.gif]

Things are going well, the theta dependence divides out

[Graphics:../Images/inviscid_sphere_gr_71.gif]
[Graphics:../Images/inviscid_sphere_gr_72.gif]

This can be solved readily with a solution of the form A[r] = rα because it is an Euler equation.  

[Graphics:../Images/inviscid_sphere_gr_73.gif]
[Graphics:../Images/inviscid_sphere_gr_74.gif]

Here is the far away boundary condition, we match the r velocity to the free stream , @ r-->∞

[Graphics:../Images/inviscid_sphere_gr_75.gif]
[Graphics:../Images/inviscid_sphere_gr_76.gif]

The boundary condition on the sphere must be [Graphics:../Images/inviscid_sphere_gr_77.gif][r=R] = 0

[Graphics:../Images/inviscid_sphere_gr_78.gif]
[Graphics:../Images/inviscid_sphere_gr_79.gif]

Now solve for the constants

[Graphics:../Images/inviscid_sphere_gr_80.gif]
[Graphics:../Images/inviscid_sphere_gr_81.gif]

Now replace the constants in the answer to get the expression for the streamlines.  

[Graphics:../Images/inviscid_sphere_gr_82.gif]
[Graphics:../Images/inviscid_sphere_gr_83.gif]
Check of potential and stream function answers


Converted by Mathematica      June 18, 2000